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陶远虎

领域:宜宾新闻网

介绍:户型结构方正布局合理主要生活空间南向,客厅开间米带米宽阳台宽敞实用。0x01提取apk中的/lib/armeabi-v7a/,0x02IDA反编译,有ptrace和kill(pid,...)反调试机制,将涉及两者的调用指令全部清零,即改为MOVSR0,R0nil指令0x03更新apk中的/lib/armeabi-v7a/,并重新签名0x04IDAadbforwardtcp:23946tcp:23946虚拟机,调试0x05提取异或EOR和base64加密的内部比对注册码xb_rkey前期混淆清除分析可以发现最终比对位置为.text000038D0,调试断下可知librf_:A46D58D0LDRBR2,[R1,R4]librf_:A46D58D2LDRBR3,[R0,R4]librf_:A46D58D4CMPR3,R2R0:异或EOR和BASE64加密的内部xb_rkeyA46F20204A50796A7570336543794A6A6C6B5636JPyjup3eCyJjlkV6A46F2030446D536D4748513D21210A0A00000000DmSmGHQ=!!......R1:异或EOR和BASE64加密的输入xb_ikeyB4B58DE0654B2F30363871525757677A78523878eK/068qRWWgzxR8xB4B58DF04247536D484874734A4D303D00000000BGSmHHtsJM0=....0x06逆向获取异或操作因子xorvector因为:xb_ikey=(ikey^xorvector)所以:xorvector=(xb_ikey)^(xb_ikey)可以从[0x05]处通过xb_ikey解码得到,也可以在base64编码前得到[]check函数在text:00005AFC开始执行base64编码,调试断下R0:(xb_ikey)A48E646078AFF4EBCA91596833C51F310464A61CA48E64707B6C24CD000000000000000000000000在IDAPpython执行下述代码可以得到注册码rkey=madebyericky94528,#0xA48E6460对应于断点处R0值importbase64b=(JPyjup3eCyJjlkV6DmSmGHQ=!!#b=$\xfc\xa3\xba\x9d\xde\x0bc\x96Ez\x0ed\xa6\x18tikey=12345678901234567890xorvector=[]rkeyL=[]foriinxrange(0,17):(Byte(0xA48E6460+i)^ord(ikey[i]))(chr(xorvector[i]^ord(b[i])))PythonrkeyL[m,a,d,e,b,y,e,r,i,c,k,y,9,4,5,2,8](rkeyL)#rkeymadebyericky94528[0x06,0x02]直接利用[0x05]中断点处信息得到注册码importbase64xb_rkey=JPyjup3eCyJjlkV6DmSmGHQ=#x_rkey=()#x_rkey=$\xfc\xa3\xba\x9d\xde\x0bc\x96Ez\x0ed\xa6\x18txb_ikey=eK/068qRWWgzxR8xBGSmHHtsJM0=x_ikey=(xb_ikey)#x_ikey=x\xaf\xf4\xeb\xca\x91Yh3\xc5\x1f1\x04d\xa6\x1c{l$\xcdikey=12345678901234567890xorvector=[]rkeyL=[]foriinxrange(0,17):(ord(x_ikey[i])^ord(ikey[i]))(chr(xorvector[i]^ord(x_rkey[i])))rkey=(rkeyL)printrkey#madebyericky945280x07MORE此方式攻击关键点是获取输入ikey对应的xb_ikey和xb_rkey=JPyjup3eCyJjlkV6DmSmGHQ=,而不同ikey对应不同xb_ikey,都可以用于获取xorvector因子;上述攻击中ikey长度取了20,实际ikey的长度最小应该为x_rkey的长度17,只要得到足够长的xorvector因子即可。,程序中包含一个驱动文件,用vs打开查看资源可以直接拿出驱动驱动里函数不多,根据DbgPrint里的字符能知道大部分函数作用有反调试,可以nop掉r3程序0x004015D4处的函数调用,保证堆栈平衡,还要nop掉0x004015D0处的函数参数简单分析加调试后知道整个程序流程是r3程序接受输入,判断长度是否为6,并转为小写倒序发送给驱动。Hi_2HexTo1Bin_Xor0x86_sub_402E20Hi_AFX_MODULE_THREAD_STATE_ctor_sub_4066D2Hi_AFX_THREAD_STATE_ctor_sub_405F63Hi_AfxGetStringManagerHi_CStr_Mid_sPos_chSize_sub_404160Hi_CStr_dotr_sub_402C70Hi_CStr_getLen_sub_4029D0Hi_DecExpand_sub_403650Hi_IDDlg_2_hWnd_sub_417026Hi_InP2DlgID_OutP3text_sub_416F7AHi_P1_EQ_EcxLeftNStr_sub_404210Hi_P2CStr_spliteAt5_to_ecx2CStrA1A2_retA2_sub_402D30Hi_RaiseException_sub_405F15Hi_afxstr_ecx_eq_p1_sub_404830Hi_bastr_ecx_eq_P1lpsz_P2len_sub_401EE0Hi_bastr_trim_sub_412460Hi_bstrReserve_sub_416A1DHi_checkKey1_or_expandKey_sub_403230Hi_check_key1_sub_403510Hi_chset_index_sub_4043C0Hi_ecxCStr_eq_P1CStr_sub_4048C0Hi_extract_key1_sub_4032C0Hi_free_sub_4AEF5FHi_getCStrPtr_sub_404280Hi_getEditText_sub_403B60Hi_getNilString_sub_4050C2Hi_getThis_sub_402080Hi_get_AFX_THREAD_STATE_sub_416D28Hi_keyMsgMap_sub_4151F8Hi_malloc_sub_404B6BHi_malloc_sub_404F1FHi_memset_ecx_0_cbSizeP1_sub_402620Hi_realloc_sub_405198...

姬显

领域:有问必答

介绍:除非自己有发展潜力,如果是借助周边辐射为主自身强度呈弱势的情况,铁路的影响就非常大了。其实就是对输入分别与下面这一串异或,返回结果。2、中考情况2016年是明德第一届参加中考,成绩相当不错。,盛典之上,一支《我们的故事》视频揭开了地产人背后的酸甜苦辣,也向大家展示了中泰人为践行诺言,使命必达的精神。...

www.vns3359.com
3nb | 2018-8-17 | 阅读(124) | 评论(60)
句柄表在EPROCESS结构体中,有一个句柄表成员:我们知道,句柄是为了操作内核对象的“序号”,它的好处在于统一了接口,使得进程(准确来说是线程)能够用统一的方式操作不同的对象资源。会议大获成功,受到了梆梆安全、腾讯安全、爱加密、几维安全、百度安全、硬土壳、金山毒霸(猎豹旗下品牌)、乐变技术、腾讯TSRC、Wifi万能钥匙、天特信息、360公司、江民科技、博文视点、华章图书、infoQ、雷锋网等数十家公司和媒体的大力支持和赞助,会场爆满。,靠花园单位的通风效果稍好一些。_QWORD*__fastcallmakeChunk(accountInfo*a1,accountInfo*a2){_QWORD*v2;//rax_QWORD*v3;//rax_QWORD*result;//raxif(a2){v2=(_QWORD*)getChunkHead((__int64)a2);init_chunk(v2);}if(a1-chunk){v3=(_QWORD*)getChunkHead(a1-chunk);free_chunk(v3);}result=a1-chunk;a1-chunk=(__int64)a2;returnresult;}unsigned__int64__fastcallfree_chunk(_QWORD*a1){__int64v1;//rax__int64v3;//[rsp+10h][rbp-20h]_QWORD*v4;//[rsp+18h][rbp-18h]__int64*v5;//[rsp+20h][rbp-10h]unsigned__int64v6;//[rsp+28h][rbp-8h]v6=__readfsqword(0x28u);v3=0LL;v4=a1;--*a1;if(!*v4){while(1){v5=(__int64*)checkIsAddr((__int64)a1,v3);if(v5==0LL)break;++v3;v1=getChunkHead(*v5);exchangeAddr(v1);}exchangeAddr((__int64)v4);}return__readfsqword(0x28u)^v6;}__int64__fastcallexchangeAddr(__int64a1){__int64result;//raxif(!newChunk)newChunk=(__int64)alloc_mem(4);*(_QWORD*)(a1+0x10)=newChunk;*(_QWORD*)newChunk=a1;result=newChunk+8;newChunk+=8LL;returnresult;}...【阅读全文】
f3b | 2018-8-17 | 阅读(579) | 评论(835)
WriteFile用来发送我们输入的注册码。这题比较简单,OD载入,代码窗口很容易找到:0040112B|.66:81BC242C010000EAcmpwordptrss:[],3EA事例111(WM_COMMAND)|.0F855B010000jne004012960040113B|.884C2420movss:[],cl0040113F|.B93F000000movecx,3F00401144|.33C0xoreax,eax00401146|.8D7C2421leaedi,[+1]0040114A|.F3:ABrepstosdwordptres:[edi]0040114C|.8BB42424010000movesi,ss:[]00401153|.8B1DA0504000movebx,ds:[&]00401159|.66:ABstoswordptres:[edi]0040115B|.8D442420leaeax,[]0040115F|.BF01000000movedi,100401164|.50pusheax/lParam=|.68FF000000push0FF|wParam=|.6A0Dpush0D|Msg=WM_GETTEXT0040116C|.68E9030000push3E9|/ItemID=|.56pushesi||hDialog=[]00401172|.FFD3callebx|\|.8B2DA4504000movebp,ds:[&]|0040117A|.50pusheax|hWnd0040117B|.FFD5callebp\|.33C9xorecx,ecx0040117F|.85C0testeax,eax00401181|.7617jbeshort0040119A00401183|8A540C20/movdl,ss:[ecx+esp+20]00401187|.80FA30|cmpdl,30//注册码全是数字0040118A|.7C0C|jlshort004011980040118C|.80FA39|cmpdl,390040118F|.7F07|jgshort0040119800401191|.41|incecx00401192|.3BC8|cmpecx,eax00401194|.^72ED\jbshort0040118300401196|.EB02jmpshort0040119A00401198|33FFxoredi,edi0040119A|83F806cmpeax,6//长度必须是60040119D|.7556jneshort004011F50040119F|.85FFtestedi,edi004011A1|.7452jzshort004011F5004011A3|.8D4C2420leaecx,[]004011A7|.50pusheax/Arg2004011A8|.51pushecx|Arg1=|.E852FEFFFFcall00401000\,//调用解码函数,对00406030的代码解码004011AE|.83C408addesp,8004011B1|.E80AFFFFFFcall004010C0//调用函数对解码后的内容进行和校验,正确返回1004011B6|.85C0testeax,eax004011B8|.742Cjzshort004011E6004011BA|.6A00push0//校验正确,调用解码后的函数提示成功004011BC|.68E9030000push3E9004011C1|.56pushesi004011C2|.FFD3callebx004011C4|.8B3DA8504000movedi,ds:[&]004011CA|.50pusheax|hWnd004011CB|.FFD7calledi\|.6A00push0004011CF|.68EA030000push3EA004011D4|.56pushesi004011D5|.FFD3callebx004011D7|.50pusheax004011D8|.FFD7calledi004011DA|.55pushebp004011DB|.56pushesi004011DC|.BA30604000movedx,offset00406030入口点004011E1|.FFD2calledx004011E3|.83C408addesp,8004011E6|8D442420leaeax,[]004011EA|.6A06push6/Arg2=6004011EC|.50pusheax|Arg1004011ED|.E80EFEFFFFcall00401000\,//再次调用解码函数恢复原来的数据004011F2|.83C408addesp,8004011F5|5Fpopedi默认情况下|.5Epopesi004011F7|.5Dpopebp004011F8|.33C0xoreax,eax004011FA|.5Bpopebx004011FB|.81C410010000addesp,11000401201|.C21000retn1000401000/$81EC08010000subesp,108//解码函数00401006|.53pushebx00401007|.55pushebp00401008|.56pushesi00401009|.57pushedi0040100A|.33D2xoredx,edx0040100C|.B93F000000movecx,3F00401011|.33C0xoreax,eax00401013|.8D7C2419leaedi,[+1]00401017|.88542418movss:[],dl0040101B|.F3:ABrepstosdwordptres:[edi]0040101D|.66:ABstoswordptres:[edi]0040101F|.AAstosbyteptres:[edi]00401020|.8D7C2418leaedi,[]00401024|.33C0xoreax,eax00401026|88440418/movss:[eax+esp+18],al0040102A|.40|inceax0040102B|.3D00010000|cmpeax,10000401030|.^7CF4\jlshort0040102600401032|.8BAC2420010000movebp,ss:[]00401039|.33C0xoreax,eax0040103B|.C744241000010000movdwordptrss:[],10000401043|8BB4241C010000/movesi,ss:[]0040104A|.8A0F|movcl,ds:[edi]0040104C|.8A1C30|movbl,ds:[esi+eax]0040104F|.02D9|addbl,cl00401051|.02D3|adddl,bl00401053|.40|inceax00401054|.88542414|movss:[],dl00401058|.8B742414|movesi,ss:[]0040105C|.81E6FF000000|andesi,000000FF00401062|.3BC5|cmpeax,ebp00401064|.8A5C3418|movbl,ss:[esi+esp+18]00401068|.8D743418|leaesi,[esi+esp+18]0040106C|.881F|movds:[edi],bl0040106E|.880E|movds:[esi],cl00401070|.7502|jneshort0040107400401072|.33C0|xoreax,eax00401074|8B4C2410|movecx,ss:[]00401078|.47|incedi00401079|.49|dececx0040107A|.894C2410|movss:[],ecx0040107E|.^75C3\jnzshort0040104300401080|.33C0xoreax,eax00401082|.8D8C2417010000leaecx,[+3]00401089|8A540418/movdl,ss:[eax+esp+18]0040108D|.8A19|movbl,ds:[ecx]0040108F|.02D3|adddl,bl00401091|.8A9830604000|movbl,ds:[eax+406030]00401097|.32DA|xorbl,dl00401099|.889830604000|movds:[eax+406030],bl0040109F|.40|inceax004010A0|.49|dececx004010A1|.3D80000000|cmpeax,80004010A6|.^7CE1\jlshort00401089004010A8|.5Fpopedi004010A9|.5Epopesi004010AA|.5Dpopebp004010AB|.5Bpopebx004010AC|.81C408010000addesp,108004010B2\.C3retn004010C0/$56pushesi//求和校验004010C1|.57pushedi004010C2|.33FFxoredi,edi004010C4|.33F6xoresi,esi004010C6|.33C9xorecx,ecx004010C8|33C0/xoreax,eax004010CA|.8A8130604000|moval,ds:[ecx+406030]004010D0|.99|cdq004010D1|.03F8|addedi,eax004010D3|.13F2|adcesi,edx004010D5|.41|incecx004010D6|.81F980000000|cmpecx,80004010DC|.^7CEA\jlshort004010C8004010DE|.81FF79290000cmpedi,2979//求和必须为0x2979004010E4|.750Cjneshort004010F2004010E6|.85F6testesi,esi004010E8|.7508jnzshort004010F2004010EA|.5Fpopedi004010EB|.B801000000moveax,1004010F0|.5Epopesi004010F1|.C3retn004010F2|5Fpopedi004010F3|.33C0xoreax,eax004010F5|.5Epopesi004010F6\.C3retn根据对上面的解码函数和校验函数分析,写出下面的代码暴力破解,从000000到999999扫描:boolkeyGen(){BYTEbuf1[0x80]={0xF4,0x12,0x9D,0x60,0x45,0xF8,0x20,0x6A,0x6F,0x67,0x04,0x71,0xC0,0x9B,0x0C,0x5A,0x1D,0x18,0x6C,0x96,0x69,0x01,0x1C,0xF4,0x7F,0x28,0x5A,0xFB,0x29,0x07,0x40,0x8B,0xD3,0xE1,0xB1,0x12,0xFB,0xCA,0x7C,0x89,0xB9,0x5A,0x30,0x70,0x9D,0x95,0x2B,0x95,0x3C,0x8D,0x2E,0x45,0xEF,0x70,0xC6,0xA3,0xB9,0xB2,0x5A,0x63,0x5F,0x03,0x33,0xB8,0x64,0x4A,0x8F,0xBC,0xF7,0x91,0x69,0x6A,0x56,0x2E,0xD4,0x6E,0x82,0x93,0xE9,0x76,0xDC,0xA3,0x6C,0x5E,0x6B,0x72,0x64,0x37,0xE7,0x15,0x17,0xAC,0x64,0x78,0xD5,0x4A,0x60,0x2D,0xF0,0x54,0xA6,0xF3,0xE8,0xE0,0xE0,0xB9,0x8F,0x85,0x90,0xE4,0xEA,0xD6,0xBB,0xB7,0x15,0x9E,0x2A,0x44,0xE7,0x31,0x63,0xAC,0x80,0x6C,0x34,0x82,0xE9,0xCF};DWORDmagic=0x2979;DWORDsum;BYTEbuf2[0x100];intidx;charsSN[7];intsn;for(sn=0sn1000000sn++){sprintf(sSN,"%06d",sn);for(idx=0idx0x100idx++){buf2[idx]=idx;}BYTEc=0;for(idx=0idx0x100idx++){BYTEc2=buf2[idx];c+=(BYTE)sSN[idx%6]+c2;buf2[idx]=buf2[c];buf2[c]=c2;}sum=0;for(idx=0idx0x80idx++){c=(buf2[idx]+buf2[0xff-idx])^buf1[idx];sum+=c;if(summagic){//大于就退出,不再浪费时间break;}}if(sum==magic){//等于,找到OutputDebugString(sSN);break;}}if(sn=1000000){OutputDebugString("未找到!");returnfalse;}returntrue;}很快能计算出结果:771535,根据相同两个操作数异或为零的特性,只要其余十个字符成五对或全部相同即可忽略,于是可以快速得到几组key"","^^^^^^^^^^^","~~~~~~~~~~~""AABBCCDDEE","ABABCDCDEE"即只要是"","^","~"三个字符中的任意一个加上其他五对字符,位置任意,就是可行的key,这是其中一种解集。者:(编程解码)(动态调试)骤:代码,定位主要流程。...【阅读全文】
jfr | 2018-8-17 | 阅读(562) | 评论(862)
  这场盛典于珠江河畔精彩上演,觥筹交错之间,西装革履,衣香鬓影;流光溢彩的会场如一颗璀璨的明珠,闪耀一城繁华。文件同时指出,严格禁止下乡利用农村宅基地建设别墅大院和私人会馆。,一个进程能够使用的句柄,都放在EPROCESS中的句柄表ObjectTable中。其实就是对输入分别与下面这一串异或,返回结果。...【阅读全文】
f15 | 2018-8-17 | 阅读(967) | 评论(48)
心怀感恩,再上征程  一个企业的成功,是拥有一群甘愿一路追随,并能始终坚持奋斗,创造佳绩的员工。北京市是全国楼市的风向标。,来源:南方都市报住宿情况:无住宿,纯走读。...【阅读全文】
dzv | 2018-8-17 | 阅读(468) | 评论(592)
1栋A座单位体具有优秀的景观优势。还是比较给力,memset这些都失败出来了,的就不行。,其二,尽快修好道路。此项计划将以大芬美术馆为核心,大芬油画村为基地,万象汇为艺术空间,从“美好新布吉、万象新生活”开始,每年共同推进布吉公众艺术计划,意图“把艺术还给大众,让布吉拥抱美好生活”。...【阅读全文】
dnn | 2018-8-16 | 阅读(403) | 评论(925)
所以继续往后看,发现奇怪之处。方框中圈的也与正规的md5算法不同:多了一些莫名其妙的操作。,4、房地产也要去产能了。OD直接运行会弹出来这个,然后就被卡了1天,哎。...【阅读全文】
hjf | 2018-8-16 | 阅读(156) | 评论(235)
,加上大部分楼盘品质整体来说表现还不错,所以此处房价相比西丽其他区域要高出不少,如宝能华府、天悦南湾、鼎盛金域世家,目前均价在7-8万。    免责声明:    1、文章部分图片来于”百度图片“、“项目效果图”;    2、因文章中文字和图片之间亦无必然联系,仅供读者参考;    3、我们所转载的所有文章、图片、音频视频文件等资料版权归版权所有人所有,因非原创文章及图片等内容无法和版权者联系,如原作者或编辑认为作品不宜上网供大家浏览,或不应无偿使用,请及时通知我们,以迅速采取适当措施,避免给双方造成不必要的经济损失。,(4)if(_mbsicmp(v8,a888aeda4ab))截取的字符串与888aeda4ab比较。Hi_2HexTo1Bin_Xor0x86_sub_402E20Hi_AFX_MODULE_THREAD_STATE_ctor_sub_4066D2Hi_AFX_THREAD_STATE_ctor_sub_405F63Hi_AfxGetStringManagerHi_CStr_Mid_sPos_chSize_sub_404160Hi_CStr_dotr_sub_402C70Hi_CStr_getLen_sub_4029D0Hi_DecExpand_sub_403650Hi_IDDlg_2_hWnd_sub_417026Hi_InP2DlgID_OutP3text_sub_416F7AHi_P1_EQ_EcxLeftNStr_sub_404210Hi_P2CStr_spliteAt5_to_ecx2CStrA1A2_retA2_sub_402D30Hi_RaiseException_sub_405F15Hi_afxstr_ecx_eq_p1_sub_404830Hi_bastr_ecx_eq_P1lpsz_P2len_sub_401EE0Hi_bastr_trim_sub_412460Hi_bstrReserve_sub_416A1DHi_checkKey1_or_expandKey_sub_403230Hi_check_key1_sub_403510Hi_chset_index_sub_4043C0Hi_ecxCStr_eq_P1CStr_sub_4048C0Hi_extract_key1_sub_4032C0Hi_free_sub_4AEF5FHi_getCStrPtr_sub_404280Hi_getEditText_sub_403B60Hi_getNilString_sub_4050C2Hi_getThis_sub_402080Hi_get_AFX_THREAD_STATE_sub_416D28Hi_keyMsgMap_sub_4151F8Hi_malloc_sub_404B6BHi_malloc_sub_404F1FHi_memset_ecx_0_cbSizeP1_sub_402620Hi_realloc_sub_405198...【阅读全文】
fvn | 2018-8-16 | 阅读(936) | 评论(442)
罗湖区成交金额TOP10根据深圳房地产信息网的监测,深业东岭以31538万元摘取罗湖区成交金额龙虎榜桂冠,向西雍睦豪庭以12657万元取得亚军排名,中海天钻以1832万元居季军。还是比较给力,memset这些都失败出来了,的就不行。,主要包括房地产开发、物业经营与服务、海外电信运营及移动互联网、大数据、金融服务、休闲娱乐等业务版块。2018安全开发者峰会是由拥有18年悠久历史的老牌安全技术社区——看雪学院举办,会议面向开发者、安全人员及高端技术从业人员,是国内开发者与安全人才的年度盛事。...【阅读全文】
pfp | 2018-8-16 | 阅读(74) | 评论(741)
这题比较简单,OD载入,代码窗口很容易找到:0040112B|.66:81BC242C010000EAcmpwordptrss:[],3EA事例111(WM_COMMAND)|.0F855B010000jne004012960040113B|.884C2420movss:[],cl0040113F|.B93F000000movecx,3F00401144|.33C0xoreax,eax00401146|.8D7C2421leaedi,[+1]0040114A|.F3:ABrepstosdwordptres:[edi]0040114C|.8BB42424010000movesi,ss:[]00401153|.8B1DA0504000movebx,ds:[&]00401159|.66:ABstoswordptres:[edi]0040115B|.8D442420leaeax,[]0040115F|.BF01000000movedi,100401164|.50pusheax/lParam=|.68FF000000push0FF|wParam=|.6A0Dpush0D|Msg=WM_GETTEXT0040116C|.68E9030000push3E9|/ItemID=|.56pushesi||hDialog=[]00401172|.FFD3callebx|\|.8B2DA4504000movebp,ds:[&]|0040117A|.50pusheax|hWnd0040117B|.FFD5callebp\|.33C9xorecx,ecx0040117F|.85C0testeax,eax00401181|.7617jbeshort0040119A00401183|8A540C20/movdl,ss:[ecx+esp+20]00401187|.80FA30|cmpdl,30//注册码全是数字0040118A|.7C0C|jlshort004011980040118C|.80FA39|cmpdl,390040118F|.7F07|jgshort0040119800401191|.41|incecx00401192|.3BC8|cmpecx,eax00401194|.^72ED\jbshort0040118300401196|.EB02jmpshort0040119A00401198|33FFxoredi,edi0040119A|83F806cmpeax,6//长度必须是60040119D|.7556jneshort004011F50040119F|.85FFtestedi,edi004011A1|.7452jzshort004011F5004011A3|.8D4C2420leaecx,[]004011A7|.50pusheax/Arg2004011A8|.51pushecx|Arg1=|.E852FEFFFFcall00401000\,//调用解码函数,对00406030的代码解码004011AE|.83C408addesp,8004011B1|.E80AFFFFFFcall004010C0//调用函数对解码后的内容进行和校验,正确返回1004011B6|.85C0testeax,eax004011B8|.742Cjzshort004011E6004011BA|.6A00push0//校验正确,调用解码后的函数提示成功004011BC|.68E9030000push3E9004011C1|.56pushesi004011C2|.FFD3callebx004011C4|.8B3DA8504000movedi,ds:[&]004011CA|.50pusheax|hWnd004011CB|.FFD7calledi\|.6A00push0004011CF|.68EA030000push3EA004011D4|.56pushesi004011D5|.FFD3callebx004011D7|.50pusheax004011D8|.FFD7calledi004011DA|.55pushebp004011DB|.56pushesi004011DC|.BA30604000movedx,offset00406030入口点004011E1|.FFD2calledx004011E3|.83C408addesp,8004011E6|8D442420leaeax,[]004011EA|.6A06push6/Arg2=6004011EC|.50pusheax|Arg1004011ED|.E80EFEFFFFcall00401000\,//再次调用解码函数恢复原来的数据004011F2|.83C408addesp,8004011F5|5Fpopedi默认情况下|.5Epopesi004011F7|.5Dpopebp004011F8|.33C0xoreax,eax004011FA|.5Bpopebx004011FB|.81C410010000addesp,11000401201|.C21000retn1000401000/$81EC08010000subesp,108//解码函数00401006|.53pushebx00401007|.55pushebp00401008|.56pushesi00401009|.57pushedi0040100A|.33D2xoredx,edx0040100C|.B93F000000movecx,3F00401011|.33C0xoreax,eax00401013|.8D7C2419leaedi,[+1]00401017|.88542418movss:[],dl0040101B|.F3:ABrepstosdwordptres:[edi]0040101D|.66:ABstoswordptres:[edi]0040101F|.AAstosbyteptres:[edi]00401020|.8D7C2418leaedi,[]00401024|.33C0xoreax,eax00401026|88440418/movss:[eax+esp+18],al0040102A|.40|inceax0040102B|.3D00010000|cmpeax,10000401030|.^7CF4\jlshort0040102600401032|.8BAC2420010000movebp,ss:[]00401039|.33C0xoreax,eax0040103B|.C744241000010000movdwordptrss:[],10000401043|8BB4241C010000/movesi,ss:[]0040104A|.8A0F|movcl,ds:[edi]0040104C|.8A1C30|movbl,ds:[esi+eax]0040104F|.02D9|addbl,cl00401051|.02D3|adddl,bl00401053|.40|inceax00401054|.88542414|movss:[],dl00401058|.8B742414|movesi,ss:[]0040105C|.81E6FF000000|andesi,000000FF00401062|.3BC5|cmpeax,ebp00401064|.8A5C3418|movbl,ss:[esi+esp+18]00401068|.8D743418|leaesi,[esi+esp+18]0040106C|.881F|movds:[edi],bl0040106E|.880E|movds:[esi],cl00401070|.7502|jneshort0040107400401072|.33C0|xoreax,eax00401074|8B4C2410|movecx,ss:[]00401078|.47|incedi00401079|.49|dececx0040107A|.894C2410|movss:[],ecx0040107E|.^75C3\jnzshort0040104300401080|.33C0xoreax,eax00401082|.8D8C2417010000leaecx,[+3]00401089|8A540418/movdl,ss:[eax+esp+18]0040108D|.8A19|movbl,ds:[ecx]0040108F|.02D3|adddl,bl00401091|.8A9830604000|movbl,ds:[eax+406030]00401097|.32DA|xorbl,dl00401099|.889830604000|movds:[eax+406030],bl0040109F|.40|inceax004010A0|.49|dececx004010A1|.3D80000000|cmpeax,80004010A6|.^7CE1\jlshort00401089004010A8|.5Fpopedi004010A9|.5Epopesi004010AA|.5Dpopebp004010AB|.5Bpopebx004010AC|.81C408010000addesp,108004010B2\.C3retn004010C0/$56pushesi//求和校验004010C1|.57pushedi004010C2|.33FFxoredi,edi004010C4|.33F6xoresi,esi004010C6|.33C9xorecx,ecx004010C8|33C0/xoreax,eax004010CA|.8A8130604000|moval,ds:[ecx+406030]004010D0|.99|cdq004010D1|.03F8|addedi,eax004010D3|.13F2|adcesi,edx004010D5|.41|incecx004010D6|.81F980000000|cmpecx,80004010DC|.^7CEA\jlshort004010C8004010DE|.81FF79290000cmpedi,2979//求和必须为0x2979004010E4|.750Cjneshort004010F2004010E6|.85F6testesi,esi004010E8|.7508jnzshort004010F2004010EA|.5Fpopedi004010EB|.B801000000moveax,1004010F0|.5Epopesi004010F1|.C3retn004010F2|5Fpopedi004010F3|.33C0xoreax,eax004010F5|.5Epopesi004010F6\.C3retn根据对上面的解码函数和校验函数分析,写出下面的代码暴力破解,从000000到999999扫描:boolkeyGen(){BYTEbuf1[0x80]={0xF4,0x12,0x9D,0x60,0x45,0xF8,0x20,0x6A,0x6F,0x67,0x04,0x71,0xC0,0x9B,0x0C,0x5A,0x1D,0x18,0x6C,0x96,0x69,0x01,0x1C,0xF4,0x7F,0x28,0x5A,0xFB,0x29,0x07,0x40,0x8B,0xD3,0xE1,0xB1,0x12,0xFB,0xCA,0x7C,0x89,0xB9,0x5A,0x30,0x70,0x9D,0x95,0x2B,0x95,0x3C,0x8D,0x2E,0x45,0xEF,0x70,0xC6,0xA3,0xB9,0xB2,0x5A,0x63,0x5F,0x03,0x33,0xB8,0x64,0x4A,0x8F,0xBC,0xF7,0x91,0x69,0x6A,0x56,0x2E,0xD4,0x6E,0x82,0x93,0xE9,0x76,0xDC,0xA3,0x6C,0x5E,0x6B,0x72,0x64,0x37,0xE7,0x15,0x17,0xAC,0x64,0x78,0xD5,0x4A,0x60,0x2D,0xF0,0x54,0xA6,0xF3,0xE8,0xE0,0xE0,0xB9,0x8F,0x85,0x90,0xE4,0xEA,0xD6,0xBB,0xB7,0x15,0x9E,0x2A,0x44,0xE7,0x31,0x63,0xAC,0x80,0x6C,0x34,0x82,0xE9,0xCF};DWORDmagic=0x2979;DWORDsum;BYTEbuf2[0x100];intidx;charsSN[7];intsn;for(sn=0sn1000000sn++){sprintf(sSN,"%06d",sn);for(idx=0idx0x100idx++){buf2[idx]=idx;}BYTEc=0;for(idx=0idx0x100idx++){BYTEc2=buf2[idx];c+=(BYTE)sSN[idx%6]+c2;buf2[idx]=buf2[c];buf2[c]=c2;}sum=0;for(idx=0idx0x80idx++){c=(buf2[idx]+buf2[0xff-idx])^buf1[idx];sum+=c;if(summagic){//大于就退出,不再浪费时间break;}}if(sum==magic){//等于,找到OutputDebugString(sSN);break;}}if(sn=1000000){OutputDebugString("未找到!");returnfalse;}returntrue;}很快能计算出结果:771535)层层传来的数据是否大于(其实此时就是),大于则。,(一开始没有注意到驱动接收的只会是小写字符,导致后面枚举时范围扩大...浪费不少时间。序号项目编号物业名称出租资产面积(㎡)招租底价㎡(每月)出租物业经营业态限定免租期(天)出租年限承租方应具备的资格条件竞标保证金10658-1702SZTC544110栋A座02层11号商铺餐饮(食堂除外)15051、竞标人为具有独立法人资格的公司或其他组织,不含个体工商户。...【阅读全文】
prd | 2018-8-15 | 阅读(779) | 评论(306)
2018年1月10日成交的300米超高层标准的商业地块,以及一幅一幅的土地公告在东部中心,是不是可以打消你的顾虑?如果这还不足以打消你的顾虑,看看正在编制的《深圳市城市总体规划(2016-2035年)》工作。当今世界,湾区已成为带动全球经济发展的重要增长极和引领技术变革的领头羊,由此衍生出的经济效应则称之为“湾区经济”。,句柄表在EPROCESS结构体中,有一个句柄表成员:我们知道,句柄是为了操作内核对象的“序号”,它的好处在于统一了接口,使得进程(准确来说是线程)能够用统一的方式操作不同的对象资源。她告诉第一财经,日前刚坐高铁到大亚湾看了数个楼盘,“我从深圳坐高铁去大亚湾,不到30分钟就到了,高铁票价30元左右。...【阅读全文】
pzh | 2018-8-15 | 阅读(25) | 评论(788)
这题比较简单,OD载入,代码窗口很容易找到:0040112B|.66:81BC242C010000EAcmpwordptrss:[],3EA事例111(WM_COMMAND)|.0F855B010000jne004012960040113B|.884C2420movss:[],cl0040113F|.B93F000000movecx,3F00401144|.33C0xoreax,eax00401146|.8D7C2421leaedi,[+1]0040114A|.F3:ABrepstosdwordptres:[edi]0040114C|.8BB42424010000movesi,ss:[]00401153|.8B1DA0504000movebx,ds:[&]00401159|.66:ABstoswordptres:[edi]0040115B|.8D442420leaeax,[]0040115F|.BF01000000movedi,100401164|.50pusheax/lParam=|.68FF000000push0FF|wParam=|.6A0Dpush0D|Msg=WM_GETTEXT0040116C|.68E9030000push3E9|/ItemID=|.56pushesi||hDialog=[]00401172|.FFD3callebx|\|.8B2DA4504000movebp,ds:[&]|0040117A|.50pusheax|hWnd0040117B|.FFD5callebp\|.33C9xorecx,ecx0040117F|.85C0testeax,eax00401181|.7617jbeshort0040119A00401183|8A540C20/movdl,ss:[ecx+esp+20]00401187|.80FA30|cmpdl,30//注册码全是数字0040118A|.7C0C|jlshort004011980040118C|.80FA39|cmpdl,390040118F|.7F07|jgshort0040119800401191|.41|incecx00401192|.3BC8|cmpecx,eax00401194|.^72ED\jbshort0040118300401196|.EB02jmpshort0040119A00401198|33FFxoredi,edi0040119A|83F806cmpeax,6//长度必须是60040119D|.7556jneshort004011F50040119F|.85FFtestedi,edi004011A1|.7452jzshort004011F5004011A3|.8D4C2420leaecx,[]004011A7|.50pusheax/Arg2004011A8|.51pushecx|Arg1=|.E852FEFFFFcall00401000\,//调用解码函数,对00406030的代码解码004011AE|.83C408addesp,8004011B1|.E80AFFFFFFcall004010C0//调用函数对解码后的内容进行和校验,正确返回1004011B6|.85C0testeax,eax004011B8|.742Cjzshort004011E6004011BA|.6A00push0//校验正确,调用解码后的函数提示成功004011BC|.68E9030000push3E9004011C1|.56pushesi004011C2|.FFD3callebx004011C4|.8B3DA8504000movedi,ds:[&]004011CA|.50pusheax|hWnd004011CB|.FFD7calledi\|.6A00push0004011CF|.68EA030000push3EA004011D4|.56pushesi004011D5|.FFD3callebx004011D7|.50pusheax004011D8|.FFD7calledi004011DA|.55pushebp004011DB|.56pushesi004011DC|.BA30604000movedx,offset00406030入口点004011E1|.FFD2calledx004011E3|.83C408addesp,8004011E6|8D442420leaeax,[]004011EA|.6A06push6/Arg2=6004011EC|.50pusheax|Arg1004011ED|.E80EFEFFFFcall00401000\,//再次调用解码函数恢复原来的数据004011F2|.83C408addesp,8004011F5|5Fpopedi默认情况下|.5Epopesi004011F7|.5Dpopebp004011F8|.33C0xoreax,eax004011FA|.5Bpopebx004011FB|.81C410010000addesp,11000401201|.C21000retn1000401000/$81EC08010000subesp,108//解码函数00401006|.53pushebx00401007|.55pushebp00401008|.56pushesi00401009|.57pushedi0040100A|.33D2xoredx,edx0040100C|.B93F000000movecx,3F00401011|.33C0xoreax,eax00401013|.8D7C2419leaedi,[+1]00401017|.88542418movss:[],dl0040101B|.F3:ABrepstosdwordptres:[edi]0040101D|.66:ABstoswordptres:[edi]0040101F|.AAstosbyteptres:[edi]00401020|.8D7C2418leaedi,[]00401024|.33C0xoreax,eax00401026|88440418/movss:[eax+esp+18],al0040102A|.40|inceax0040102B|.3D00010000|cmpeax,10000401030|.^7CF4\jlshort0040102600401032|.8BAC2420010000movebp,ss:[]00401039|.33C0xoreax,eax0040103B|.C744241000010000movdwordptrss:[],10000401043|8BB4241C010000/movesi,ss:[]0040104A|.8A0F|movcl,ds:[edi]0040104C|.8A1C30|movbl,ds:[esi+eax]0040104F|.02D9|addbl,cl00401051|.02D3|adddl,bl00401053|.40|inceax00401054|.88542414|movss:[],dl00401058|.8B742414|movesi,ss:[]0040105C|.81E6FF000000|andesi,000000FF00401062|.3BC5|cmpeax,ebp00401064|.8A5C3418|movbl,ss:[esi+esp+18]00401068|.8D743418|leaesi,[esi+esp+18]0040106C|.881F|movds:[edi],bl0040106E|.880E|movds:[esi],cl00401070|.7502|jneshort0040107400401072|.33C0|xoreax,eax00401074|8B4C2410|movecx,ss:[]00401078|.47|incedi00401079|.49|dececx0040107A|.894C2410|movss:[],ecx0040107E|.^75C3\jnzshort0040104300401080|.33C0xoreax,eax00401082|.8D8C2417010000leaecx,[+3]00401089|8A540418/movdl,ss:[eax+esp+18]0040108D|.8A19|movbl,ds:[ecx]0040108F|.02D3|adddl,bl00401091|.8A9830604000|movbl,ds:[eax+406030]00401097|.32DA|xorbl,dl00401099|.889830604000|movds:[eax+406030],bl0040109F|.40|inceax004010A0|.49|dececx004010A1|.3D80000000|cmpeax,80004010A6|.^7CE1\jlshort00401089004010A8|.5Fpopedi004010A9|.5Epopesi004010AA|.5Dpopebp004010AB|.5Bpopebx004010AC|.81C408010000addesp,108004010B2\.C3retn004010C0/$56pushesi//求和校验004010C1|.57pushedi004010C2|.33FFxoredi,edi004010C4|.33F6xoresi,esi004010C6|.33C9xorecx,ecx004010C8|33C0/xoreax,eax004010CA|.8A8130604000|moval,ds:[ecx+406030]004010D0|.99|cdq004010D1|.03F8|addedi,eax004010D3|.13F2|adcesi,edx004010D5|.41|incecx004010D6|.81F980000000|cmpecx,80004010DC|.^7CEA\jlshort004010C8004010DE|.81FF79290000cmpedi,2979//求和必须为0x2979004010E4|.750Cjneshort004010F2004010E6|.85F6testesi,esi004010E8|.7508jnzshort004010F2004010EA|.5Fpopedi004010EB|.B801000000moveax,1004010F0|.5Epopesi004010F1|.C3retn004010F2|5Fpopedi004010F3|.33C0xoreax,eax004010F5|.5Epopesi004010F6\.C3retn根据对上面的解码函数和校验函数分析,写出下面的代码暴力破解,从000000到999999扫描:boolkeyGen(){BYTEbuf1[0x80]={0xF4,0x12,0x9D,0x60,0x45,0xF8,0x20,0x6A,0x6F,0x67,0x04,0x71,0xC0,0x9B,0x0C,0x5A,0x1D,0x18,0x6C,0x96,0x69,0x01,0x1C,0xF4,0x7F,0x28,0x5A,0xFB,0x29,0x07,0x40,0x8B,0xD3,0xE1,0xB1,0x12,0xFB,0xCA,0x7C,0x89,0xB9,0x5A,0x30,0x70,0x9D,0x95,0x2B,0x95,0x3C,0x8D,0x2E,0x45,0xEF,0x70,0xC6,0xA3,0xB9,0xB2,0x5A,0x63,0x5F,0x03,0x33,0xB8,0x64,0x4A,0x8F,0xBC,0xF7,0x91,0x69,0x6A,0x56,0x2E,0xD4,0x6E,0x82,0x93,0xE9,0x76,0xDC,0xA3,0x6C,0x5E,0x6B,0x72,0x64,0x37,0xE7,0x15,0x17,0xAC,0x64,0x78,0xD5,0x4A,0x60,0x2D,0xF0,0x54,0xA6,0xF3,0xE8,0xE0,0xE0,0xB9,0x8F,0x85,0x90,0xE4,0xEA,0xD6,0xBB,0xB7,0x15,0x9E,0x2A,0x44,0xE7,0x31,0x63,0xAC,0x80,0x6C,0x34,0x82,0xE9,0xCF};DWORDmagic=0x2979;DWORDsum;BYTEbuf2[0x100];intidx;charsSN[7];intsn;for(sn=0sn1000000sn++){sprintf(sSN,"%06d",sn);for(idx=0idx0x100idx++){buf2[idx]=idx;}BYTEc=0;for(idx=0idx0x100idx++){BYTEc2=buf2[idx];c+=(BYTE)sSN[idx%6]+c2;buf2[idx]=buf2[c];buf2[c]=c2;}sum=0;for(idx=0idx0x80idx++){c=(buf2[idx]+buf2[0xff-idx])^buf1[idx];sum+=c;if(summagic){//大于就退出,不再浪费时间break;}}if(sum==magic){//等于,找到OutputDebugString(sSN);break;}}if(sn=1000000){OutputDebugString("未找到!");returnfalse;}returntrue;}很快能计算出结果:771535深圳有数不清的赵丹丹,这个话题早已成为群体性焦虑。,Hi_2HexTo1Bin_Xor0x86_sub_402E20Hi_AFX_MODULE_THREAD_STATE_ctor_sub_4066D2Hi_AFX_THREAD_STATE_ctor_sub_405F63Hi_AfxGetStringManagerHi_CStr_Mid_sPos_chSize_sub_404160Hi_CStr_dotr_sub_402C70Hi_CStr_getLen_sub_4029D0Hi_DecExpand_sub_403650Hi_IDDlg_2_hWnd_sub_417026Hi_InP2DlgID_OutP3text_sub_416F7AHi_P1_EQ_EcxLeftNStr_sub_404210Hi_P2CStr_spliteAt5_to_ecx2CStrA1A2_retA2_sub_402D30Hi_RaiseException_sub_405F15Hi_afxstr_ecx_eq_p1_sub_404830Hi_bastr_ecx_eq_P1lpsz_P2len_sub_401EE0Hi_bastr_trim_sub_412460Hi_bstrReserve_sub_416A1DHi_checkKey1_or_expandKey_sub_403230Hi_check_key1_sub_403510Hi_chset_index_sub_4043C0Hi_ecxCStr_eq_P1CStr_sub_4048C0Hi_extract_key1_sub_4032C0Hi_free_sub_4AEF5FHi_getCStrPtr_sub_404280Hi_getEditText_sub_403B60Hi_getNilString_sub_4050C2Hi_getThis_sub_402080Hi_get_AFX_THREAD_STATE_sub_416D28Hi_keyMsgMap_sub_4151F8Hi_malloc_sub_404B6BHi_malloc_sub_404F1FHi_memset_ecx_0_cbSizeP1_sub_402620Hi_realloc_sub_405198于是,一大批缺乏实力、没有经验、负债累累的中小型房企死去,行业被集中在若干个大型房企中,既方便管理,又风险可控。...【阅读全文】
fpp | 2018-8-15 | 阅读(163) | 评论(80)
龙岗区成交量全市最高,成交1726套二手房,环比减少%,同比增加%;成交面积149763平方米,环比减少%,同比增加%。  》》》  》》》提问:2015年有一段时间祝总无任,当时短暂的一段时间是因为什么原因?郁亮:在当时有一些报道不准确,祝九胜从2012年入职一直在公司,从来没有离开过,只是当时做的工作有一些差异。,当今世界,湾区已成为带动全球经济发展的重要增长极和引领技术变革的领头羊,由此衍生出的经济效应则称之为“湾区经济”。  优越的交通位置使得雅居乐民森迪茵湖小镇非常具有发展潜力。...【阅读全文】
1vf | 2018-8-15 | 阅读(925) | 评论(977)
return16;}//CRC32编码intgetTheKey2(unsignedchar*buf,intbufsize){DWORDret=-1;DWORD*bb=(DWORD*)aa;for(inti=0;ibufsize;i++){intxt=(ret0xff)^buf[i];ret=bb[1+xt]^(ret}return~ret;}unsignedcharbuf[4]={0};intget2(DWORDa){DWORDconfirm1=0x9e;//0x9eb3acb8==~0x614C5347DWORDconfirm2=0xb3;DWORDconfirm3=0xac;DWORDconfirm4=0xb8;DWORDtmp,x[4]={0};inti,y[4]={0};DWORD*bb=(DWORD*)aa;for(i=1;i=0x100;i++){tmp=bb[i]if(tmp==confirm1){x[0]=bb[i];y[0]=i;break;}}tmp=x[0]tmp=tmp0xff;confirm2=confirm2^tmp;for(i=1;i=0x100;i++){tmp=bb[i]if(tmp==confirm2){x[1]=bb[i];y[1]=i;break;}}tmp=x[0]tmp=tmp0xff;confirm3=confirm3^tmp;tmp=x[1]tmp=tmp0xff;confirm3=confirm3^tmp;for(i=1;i=0x100;i++){tmp=bb[i]if(tmp==confirm3){x[2]=bb[i];y[2]=i;break;}}tmp=x[0];tmp=tmp0xff;confirm4=confirm4^tmp;tmp=x[1]tmp=tmp0xff;confirm4=confirm4^tmp;tmp=x[2]tmp=tmp0xff;confirm4=confirm4^tmp;for(i=1;i=0x100;i++){tmp=bb[i]if(tmp==confirm4){x[3]=bb[i];y[3]=i;break;}}DWORDret=a;//0x32f38783;for(i=3;ii--){buf[3-i]=((ret0xff)^y[i]-1);ret=x[i]^(ret}return0;}//FNV-1aHash运算DWORDgetTheKey3(unsignedchar*buf,intbufsize){DWORDret=0x811C9DC5;for(inti=0;ibufsize;i++){DWORDxx=(DWORD)buf[i];ret=0x1000193*(ret^xx);}returnret;}intget3(DWORDa){unsignedchardd[4]={0x5C,0xA4,0x88,0xC9};DWORDret=a;inti,j;for(i=0;;i++)//614C5347-A19947FD-CE19CA2F-92F5E675-F4659CD7-0D33122D-F32BF53F-66263925-7BDE6D67-127F995D-CDAA8F4F-8379C0D5{for(j=0;jj++){DWORDxx=(DWORD)dd[j];ret=0x1000193*(ret^xx);//359C449B(1000193^-1)}if(ret==0x614C5347||ret==a)//0x614C5347{break;}}if(ret==0x614C5347){returni;}else{return-1;}}for(unsignedchari=0;i0xff;i++){bbuf[xs-1]=i;DWORDyy1=getTheKey2(bbuf,xs);get2(yy1);bbuf[xs]=buf[0];bbuf[xs+1]=buf[1];bbuf[xs+2]=buf[2];bbuf[xs+3]=buf[3];//DWORDyy1=sub_1244(bbuf,xs);DWORDyy2=getTheKey3(bbuf,xs+4);intudd=get3(yy2);if(udd!=-1){printf(%02X%08X,i,udd);}}bbuf[xs-1]=0x20;DWORDyy1=getTheKey2(bbuf,xs);get2(~yy1);bbuf[xs]=buf[0];bbuf[xs+1]=buf[1];bbuf[xs+2]=buf[2];bbuf[xs+3]=buf[3];DWORDyy2=getTheKey3(bbuf,xs+4);intudd=get3(yy2);unsignedchar*memm=(unsignedchar*)malloc(udd*4+8+xs);memcpy(memm,bbuf,xs+4);for(inti=0;i=udd;i++){memm[xs+4+i*4+0]=0x5C;memm[xs+4+i*4+1]=0xA4;memm[xs+4+i*4+2]=0x88;memm[xs+4+i*4+3]=0xC9;}fp=fopen(zapus_,wb);fwrite(memm,udd*4+8+xs,1,fp);fclose(fp);上传的附件:。,没有查这个结构体,据猜测应该是把调试端口清零了。教育方面,北理莫斯科大学正式开学,龙岗大学城也引进诸多名校。...【阅读全文】
tv3 | 2018-8-14 | 阅读(635) | 评论(771)
。2018安全开发者峰会是由拥有18年悠久历史的老牌安全技术社区——看雪学院举办,会议面向开发者、安全人员及高端技术从业人员,是国内开发者与安全人才的年度盛事。,分割边界是前五个字符为key1,剩下的为key2即key=key1+:00403EEEmoveax,[ebp+var_118_thisPtr].text:00403EF4addeax.....text:00403F17pushesi;void*.text:00403F18leaecx,[ebp+var_18_2Cstr].text:00403F1BcallHi_P2CStr_spliteAt5_to_ecx2CStrA1A2_retA2_sub_402D30在重入函数Hi_checkKey1_or_expandKey_sub_403230中,第一此调用该函数体时会触发对key1的校验分支。此项计划将以大芬美术馆为核心,大芬油画村为基地,万象汇为艺术空间,从“美好新布吉、万象新生活”开始,每年共同推进布吉公众艺术计划,意图“把艺术还给大众,让布吉拥抱美好生活”。...【阅读全文】
jrl | 2018-8-14 | 阅读(243) | 评论(238)
同时,应勇也表示要“落实相应的公共服务”。在编辑框Edit控件的消息响应函数Hi_WM_COMMAND_sub_401570中通过每次输入是,都会调用消息响应函数,函数通过UpdateData(True)将当前输入的key文本更新赋值给Edit控件关联的CString成员变量,从下属代码中,可见edit控件关联成员变量在控件的0x60偏移处,要求输入的key文本长度大于0x0B,如果是正常直接输入,在输入第0x0B个字符时,就会响应校验,最大输入是0x0B;但这里的bug是,如果是复制粘贴的,其长度就可以任意,如"AAAAAAAAAAAAAAAA".text::0040158Fmov[esp+8Ch+var_74_thisPtr],:00401593callCWnd::UpdateData(int).text:00401598leaecx,[esp+88h+var_7C].text:0040159CcallCString::CString(void).text:004015A1moveax,[esi+60h].text:004015A4leaedx,[esi+60h].text:004015A7mov[esp+88h+var_4],:004015B2movebp,[eax-8].text:004015B5cmpebp,0Bh核心逻辑是两个迭代异或解密a.用用户输入的key的每一个字节异或上encKeyA=Hi_encKeyA_byte_403020,的每一个字节,解密出decKeyAb.用"a."得到的decKeyA的每一个字节有符号乘0x5E后在异或上加密代码Hi_encChipCode_sub_401540的每一个字节,解密出代码最后调用解密的代码显示成功信息。,尤其是1栋A座可见无遮挡景观的单位。其中,三块“只租不售”地块及“限售5年”地块为G02405-0007、G05425-1027、G13302-8025及G13302-8024,分别位于龙岗宝龙、龙岗平湖、坪山新区(1纯租,1限售,两地块相连)。...【阅读全文】
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